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Answer
False
The second will fail, complaining "/bin/ls: invalid option -- "
It's the same as typing "ls '-l -R'" at the command line: the arguments get passed as ONE argument and "ls" gets confused. This is the kernel at work, not the shell. When it sees "#!", the first token after that becomes the pathname to be executed, and the rest is packed into argv[1] (argv[2] is the script filename).
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Fri Sep 19 10:41:09 2008 anonymous
i tried this on terminal and both are working fine
Wed Jun 24 12:25:22 2009 Nenad
The previous comment on this question is not right.
Whatever guy in the previous comment tried, didn't do it right :)
The answer is: FALSE
It's FALSE because it cannot work when put in the script.
You can try it by putting ls '-l -R' in the console.
this is the output:
# ls '-l -R'
/bin/ls: invalid option --
Try `/bin/ls --help' for more information.
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